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A277512
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Numbers n such that A277118(n) = 15.
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1
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13, 88, 5708, 15095, 18300, 20718, 23424, 45625, 59638, 63958, 66438, 71747, 78239, 154992, 225235, 411285, 418434, 550190, 571439, 743873, 883958, 938420, 989479, 1169298, 1198004, 1256049
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OFFSET
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1,1
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COMMENTS
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Let p=A001359(n-1). Then n is in the sequence if and only if we have one of constellations of eight consecutive primes: {p=30t+29 (t>=0), p+2,p+8, p+12,p+18, p+24,p+30,p+32}, {p,p+2,p+8,p+14,p+20,p+24,p+30,p+32}, {p,p+2, p+8,p+14, p+18,p+24,p+30,p+32}.
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LINKS
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EXAMPLE
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a(1)=13, then we have one of three mentioned in comment constellations of 8 consecutive primes: p=A001359(12)=149, 151, 157, 163, 167, 173, 179 and 181.
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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STATUS
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approved
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