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Revision History for A086106

(Underlined text is an addition; strikethrough text is a deletion.)

Showing entries 1-10 | older changes
A086106 Decimal expansion of positive root of x^4 - x^3 - 1 = 0.
(history; published version)
#42 by Charles R Greathouse IV at Mon Aug 21 10:19:07 EDT 2023
STATUS

editing

approved

#41 by Charles R Greathouse IV at Mon Aug 21 10:19:06 EDT 2023
LINKS

<a href="/index/Al#algebraic_04">Index entries for algebraic numbers, degree 4</a>

PROG

(PARI) { ) default(realprecision, 20080); x=solve(x=1, 2, x^4 - x^3 - 1); for (n=1, 20000, d=floor(x); x=(x-d)*10; write("b086106.txt", n, " ", d)); } \\ _)); \\ _Iain Fox_, Oct 23 2017

STATUS

approved

editing

#40 by N. J. A. Sloane at Tue Aug 23 10:02:54 EDT 2022
STATUS

proposed

approved

#39 by Wolfdieter Lang at Tue Aug 23 06:40:40 EDT 2022
STATUS

editing

proposed

#38 by Wolfdieter Lang at Tue Aug 23 06:34:48 EDT 2022
FORMULA

Equals (1 + (A^2 + sqrt(A^4 - 16*u*A^2 + 2*A))/A)/4 with A = sqrt(8*u + 3/2), u = (-(Bp/2)^(1/3) + (Bm/2)^(1/3)*(1 - sqrt(3)*i)/2 - 3/8)/6. , with Bp = 27 + 3*sqrt(3*283), Bm = 27 - 3*sqrt(3*283), and i = sqrt(-1). (Standard computation of a quartic.) The other (negative) real root -A230151 is obtained by using in the first formula the negative square root. The other two complex roots are obtained by replacing A by -A in these two formulas. - Wolfdieter Lang, Aug 19 2022

STATUS

proposed

editing

Discussion
Tue Aug 23 06:40
Wolfdieter Lang: Thanks Jon, the period should have been a comma. Concerning my permution edit , using bad English as you remarked,  was only because I didn't see a pink box. Next time I'll tro find the pink box.
#37 by Wolfdieter Lang at Mon Aug 22 06:12:44 EDT 2022
STATUS

editing

proposed

Discussion
Tue Aug 23 03:25
Jon E. Schoenfield: Thanks! Until reading your comment there just now, I don’t remember ever having seen anything indicating that the notation “choose(n,m)” might, in some situations, mean something other than “binomial(n,m)”! Now I know and will be more careful about that!
03:32
Jon E. Schoenfield: But I don’t understand what you meant when you wrote “I did this permutation in order to be able to write a pink box comment”. By “this permutation”, do you mean the edit that resulted in Revision #36? If so, I don’t understand, because this draft was in proposed mode, so you or I or anyone would have been able to write a pink-box comment, with or without making any edit. But if you meant something else by “this permutation”, then I have no idea what that was. ?:-/
03:35
Jon E. Schoenfield: Is the period in “:6. with Bp =” a mistake?
03:51
Jon E. Schoenfield: About “replacing this with that” vs. “replacing this by that”: I frequently hear well-educated native speakers of English say things like “This bulb is burned out. I need to replace it with a new one.” Or “These tires are too worn. You need to replace them with new ones.” Or “My old phone was unreliable, so I replaced it with a new one.” I’ve never heard a native speaker of English, in any sentence like one of those, speak of replacing a thing “by” a new one. I think a similar situation applies to “are obtained by replacing A with -A” vs. “are obtained by replacing A by -A”.
03:54
Jon E. Schoenfield: I’m sorry, in my comment at 03:35 (insomnia time), I made a mistake. I meant to send this: Is the period in “/6. with Bp =” a mistake?
#36 by Wolfdieter Lang at Mon Aug 22 06:06:33 EDT 2022
FORMULA

Equals (1 + (A^2 + sqrt(A^4 - 16*u*A^2 + 2*A))/A)/4 with A = sqrt(8*u + 3/2), u = (-(Bp/2)^(1/3) + (Bm/2)^(1/3)*(1 - sqrt(3)*i)/2 - 3/8)/6. with Bp = 27 + 3*sqrt(3*283), Bm = 27 - 3*sqrt(3*283), and i = sqrt(-1). (Standard computation of a quartic.) The other (negative) real root -A230151 is obtained by using in the first formula the negative square root. The other two complex roots are obtained by replacing A by -A in these two formulas A by -A. - Wolfdieter Lang, Aug 19 2022

STATUS

proposed

editing

Discussion
Mon Aug 22 06:12
Wolfdieter Lang: Thanks Jon, (I did this permutation in order to be able to write a pink box comment). [By the way, you could  have a look at my comment on choose(n, m) versus binomial (n, m) in A134346 (after edition  Nr.30).]
#35 by Michel Marcus at Mon Aug 22 01:44:57 EDT 2022
STATUS

editing

proposed

#34 by Michel Marcus at Mon Aug 22 01:44:24 EDT 2022
LINKS

A. Stakhov, and B. Rozin, <a href="http://dx.doi.org/10.1016/j.chaos.2005.04.106">Theory of Binet formulas for Fibonacci and Lucas p-numbers</a>, Chaos, Solit. Fractals 27 (2006), 1162-1177.

STATUS

proposed

editing

#33 by Wolfdieter Lang at Sun Aug 21 18:04:47 EDT 2022
STATUS

editing

proposed

Discussion
Sun Aug 21 20:52
Jon E. Schoenfield: At the sentence "The other two complex roots are obtained by replacing in these two formulas A by -A", I think the native speakers of English whom I've met would say "The other two complex roots are obtained by replacing A with -A in these two formulas."

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Last modified September 16 07:48 EDT 2024. Contains 375959 sequences. (Running on oeis4.)