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#14 by Joerg Arndt at Mon Dec 04 02:55:20 EST 2017
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#13 by Jon E. Schoenfield at Sun Dec 03 22:50:26 EST 2017
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#12 by Jon E. Schoenfield at Sun Dec 03 22:50:23 EST 2017
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| NAME
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a(n) = 2^bil(n) - bil(n) where bil(0) = 0 and bil(n) = floor(log_2(n)) + 1 for n> > 0.
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| FORMULA
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a(n)=) = 4*a(floor(n/2))-)) - 5*a(floor(n/4))+)) + 2*a(floor(n/8)) for n >= 4. (End)
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| STATUS
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proposed
editing
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#11 by Robert Israel at Sun Dec 03 21:46:49 EST 2017
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#10 by Robert Israel at Sun Dec 03 21:46:42 EST 2017
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| LINKS
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Robert Israel, <a href="/A295514/b295514.txt">Table of n, a(n) for n = 0..10000</a>
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| FORMULA
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From Robert Israel, Dec 03 2017: (Start)
G.f. (1-x)^(-1)*(1+Sum_{k>=0} (2^k-1)*x^(2^k)). - _Robert Israel_, Dec 03 2017)).
a(n)=4*a(floor(n/2))-5*a(floor(n/4))+2*a(floor(n/8)) for n >= 4. (End)
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#9 by Robert Israel at Sun Dec 03 21:37:04 EST 2017
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| FORMULA
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G.f. (1-x)^(-1)*(1+Sum_{k>=0} (2^k-1)*x^(2^k)). - Robert Israel, Dec 03 2017
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| MAPLE
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1, seq((2^k-k)$(2^(k-1)), k=1..8); # Robert Israel, Dec 03 2017
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| STATUS
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approved
editing
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#8 by Peter Luschny at Sat Dec 02 10:04:49 EST 2017
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#7 by Joerg Arndt at Sat Dec 02 08:45:53 EST 2017
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#6 by David A. Corneth at Sat Dec 02 07:10:05 EST 2017
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#5 by David A. Corneth at Sat Dec 02 07:09:12 EST 2017
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| CROSSREFS
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Cf. A000325.
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| STATUS
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proposed
editing
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